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20+7X-6X^2=0
a = -6; b = 7; c = +20;
Δ = b2-4ac
Δ = 72-4·(-6)·20
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*-6}=\frac{-30}{-12} =2+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*-6}=\frac{16}{-12} =-1+1/3 $
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